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190092417439 is a prime number
BaseRepresentation
bin1011000100001001100…
…1000001100110011111
3200011122212102100021011
42301002121001212133
511103302124324224
6223154404120051
716506444613441
oct2610231014637
9604585370234
10190092417439
1173688239841
1230a11696027
1314c0581c0a2
1492b4338491
154e2876e394
hex2c4264199f

190092417439 has 2 divisors, whose sum is σ = 190092417440. Its totient is φ = 190092417438.

The previous prime is 190092417421. The next prime is 190092417461. The reversal of 190092417439 is 934714290091.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 190092417439 - 219 = 190091893151 is a prime.

It is a super-3 number, since 3×1900924174393 (a number of 35 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.

It is a junction number, because it is equal to n+sod(n) for n = 190092417392 and 190092417401.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (190092417239) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 95046208719 + 95046208720.

It is an arithmetic number, because the mean of its divisors is an integer number (95046208720).

Almost surely, 2190092417439 is an apocalyptic number.

190092417439 is a deficient number, since it is larger than the sum of its proper divisors (1).

190092417439 is an equidigital number, since it uses as much as digits as its factorization.

190092417439 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 489888, while the sum is 49.

The spelling of 190092417439 in words is "one hundred ninety billion, ninety-two million, four hundred seventeen thousand, four hundred thirty-nine".