Base | Representation |
---|---|
bin | 1011000101000111111… |
… | …1010111000010001101 |
3 | 200012100002212110110121 |
4 | 2301101333113002031 |
5 | 11104321123444231 |
6 | 223240353304541 |
7 | 16516103236201 |
oct | 2612177270215 |
9 | 605302773417 |
10 | 190354124941 |
11 | 73801a39532 |
12 | 30a85265151 |
13 | 14c47b005b6 |
14 | 92dadc0b01 |
15 | 4e41717311 |
hex | 2c51fd708d |
190354124941 has 2 divisors, whose sum is σ = 190354124942. Its totient is φ = 190354124940.
The previous prime is 190354124927. The next prime is 190354124951. The reversal of 190354124941 is 149421453091.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 164487836041 + 25866288900 = 405571^2 + 160830^2 .
It is a cyclic number.
It is not a de Polignac number, because 190354124941 - 27 = 190354124813 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (190354124951) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 95177062470 + 95177062471.
It is an arithmetic number, because the mean of its divisors is an integer number (95177062471).
Almost surely, 2190354124941 is an apocalyptic number.
It is an amenable number.
190354124941 is a deficient number, since it is larger than the sum of its proper divisors (1).
190354124941 is an equidigital number, since it uses as much as digits as its factorization.
190354124941 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 155520, while the sum is 43.
The spelling of 190354124941 in words is "one hundred ninety billion, three hundred fifty-four million, one hundred twenty-four thousand, nine hundred forty-one".
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