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19144013988433 is a prime number
BaseRepresentation
bin1000101101001010100000…
…01001110100001001010001
32111210011001020202200220011
410112211100021310021101
510002123420040112213
6104414345535114521
74014052340666215
oct426452011641121
974704036680804
1019144013988433
116110a268a41a4
1221922a3672a41
13a8b371388989
144a280a598945
15232ea692b03d
hex116950274251

19144013988433 has 2 divisors, whose sum is σ = 19144013988434. Its totient is φ = 19144013988432.

The previous prime is 19144013988401. The next prime is 19144013988469. The reversal of 19144013988433 is 33488931044191.

It is a happy number.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 10550134121409 + 8593879867024 = 3248097^2 + 2931532^2 .

It is a cyclic number.

It is not a de Polignac number, because 19144013988433 - 25 = 19144013988401 is a prime.

It is not a weakly prime, because it can be changed into another prime (19144013988833) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 9572006994216 + 9572006994217.

It is an arithmetic number, because the mean of its divisors is an integer number (9572006994217).

Almost surely, 219144013988433 is an apocalyptic number.

It is an amenable number.

19144013988433 is a deficient number, since it is larger than the sum of its proper divisors (1).

19144013988433 is an equidigital number, since it uses as much as digits as its factorization.

19144013988433 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 8957952, while the sum is 58.

The spelling of 19144013988433 in words is "nineteen trillion, one hundred forty-four billion, thirteen million, nine hundred eighty-eight thousand, four hundred thirty-three".