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19151490506047 is a prime number
BaseRepresentation
bin1000101101011000011011…
…10010011101110100111111
32111210212100022011010221221
410112230031302131310333
510002234223032143142
6104422023454534211
74014435534230524
oct426541562356477
974725308133857
1019151490506047
116114113126579
12219382b507367
13a8bc933144b3
144a2d1951714b
15233292ec0767
hex116b0dc9dd3f

19151490506047 has 2 divisors, whose sum is σ = 19151490506048. Its totient is φ = 19151490506046.

The previous prime is 19151490506011. The next prime is 19151490506081. The reversal of 19151490506047 is 74060509415191.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 19151490506047 - 243 = 10355397483839 is a prime.

It is a super-2 number, since 2×191514905060472 (a number of 27 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 19151490505985 and 19151490506003.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (19151490536047) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 9575745253023 + 9575745253024.

It is an arithmetic number, because the mean of its divisors is an integer number (9575745253024).

Almost surely, 219151490506047 is an apocalyptic number.

19151490506047 is a deficient number, since it is larger than the sum of its proper divisors (1).

19151490506047 is an equidigital number, since it uses as much as digits as its factorization.

19151490506047 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 1360800, while the sum is 52.

The spelling of 19151490506047 in words is "nineteen trillion, one hundred fifty-one billion, four hundred ninety million, five hundred six thousand, forty-seven".