Base | Representation |
---|---|
bin | 10001110110111100… |
… | …000011110111001110 |
3 | 1211111100202110000012 |
4 | 101312330003313032 |
5 | 303232340401014 |
6 | 12450425433222 |
7 | 1246116401000 |
oct | 216674036716 |
9 | 54440673005 |
10 | 19175325134 |
11 | 814aa75649 |
12 | 387193b812 |
13 | 1a67895844 |
14 | cdc976370 |
15 | 77366cc3e |
hex | 476f03dce |
19175325134 has 72 divisors (see below), whose sum is σ = 35746957200. Its totient is φ = 7709714880.
The previous prime is 19175325131. The next prime is 19175325139. The reversal of 19175325134 is 43152357191.
It is a super-2 number, since 2×191753251342 (a number of 21 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 19175325091 and 19175325100.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (19175325131) by changing a digit.
It is a polite number, since it can be written in 35 ways as a sum of consecutive naturals, for example, 61656839 + ... + 61657149.
Almost surely, 219175325134 is an apocalyptic number.
19175325134 is a gapful number since it is divisible by the number (14) formed by its first and last digit.
19175325134 is a deficient number, since it is larger than the sum of its proper divisors (16571632066).
19175325134 is an frugal number, since it uses more digits than its factorization.
19175325134 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 679 (or 337 counting only the distinct ones).
The product of its digits is 113400, while the sum is 41.
The spelling of 19175325134 in words is "nineteen billion, one hundred seventy-five million, three hundred twenty-five thousand, one hundred thirty-four".
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