Search a number
-
+
19175553420131 is a prime number
BaseRepresentation
bin1000101110000101010000…
…00011001100101101100011
32111220011110021202211120002
410113002220003030231203
510003133013133421011
6104441043322410215
74016250042513143
oct427025003145543
974804407684502
1019175553420131
116123341000029
12219842606096b
13a9132966acb4
144a415d24c923
15233c0078cc3b
hex1170a80ccb63

19175553420131 has 2 divisors, whose sum is σ = 19175553420132. Its totient is φ = 19175553420130.

The previous prime is 19175553420043. The next prime is 19175553420143. The reversal of 19175553420131 is 13102435557191.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 19175553420131 - 210 = 19175553419107 is a prime.

It is a super-2 number, since 2×191755534201312 (a number of 27 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (19175553420161) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 9587776710065 + 9587776710066.

It is an arithmetic number, because the mean of its divisors is an integer number (9587776710066).

Almost surely, 219175553420131 is an apocalyptic number.

19175553420131 is a deficient number, since it is larger than the sum of its proper divisors (1).

19175553420131 is an equidigital number, since it uses as much as digits as its factorization.

19175553420131 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 567000, while the sum is 47.

The spelling of 19175553420131 in words is "nineteen trillion, one hundred seventy-five billion, five hundred fifty-three million, four hundred twenty thousand, one hundred thirty-one".