Search a number
-
+
1918041300 = 22325272233161
BaseRepresentation
bin111001001010010…
…1111110011010100
311221200010121000200
41302110233303110
512412004310200
6514154140500
765350040100
oct16224576324
94850117020
101918041300
118a47588aa
12456421730
132474ac5a6
14142a42900
15b35c3800
hex7252fcd4

1918041300 has 648 divisors, whose sum is σ = 7656509952. Its totient is φ = 399168000.

The previous prime is 1918041289. The next prime is 1918041341. The reversal of 1918041300 is 31408191.

It is a congruent number.

It is an unprimeable number.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 215 ways as a sum of consecutive naturals, for example, 31443270 + ... + 31443330.

Almost surely, 21918041300 is an apocalyptic number.

1918041300 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 1918041300, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (3828254976).

1918041300 is an abundant number, since it is smaller than the sum of its proper divisors (5738468652).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

1918041300 is a wasteful number, since it uses less digits than its factorization.

1918041300 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 149 (or 132 counting only the distinct ones).

The product of its (nonzero) digits is 864, while the sum is 27.

The square root of 1918041300 is about 43795.4483936402. The cubic root of 1918041300 is about 1242.4702102228.

Adding to 1918041300 its reverse (31408191), we get a palindrome (1949449491).

The spelling of 1918041300 in words is "one billion, nine hundred eighteen million, forty-one thousand, three hundred".