1918050943 has 2 divisors, whose sum is σ = 1918050944. Its totient is φ = 1918050942.

The previous prime is 1918050919. The next prime is 1918050947. The reversal of 1918050943 is 3490508191.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 1918050943 - 2¹³ = 1918042751 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 1918050896 and 1918050905.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1918050947) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 959025471 + 959025472.

It is an arithmetic number, because the mean of its divisors is an integer number (959025472).

Almost surely, 2^1918050943 is an apocalyptic number.

1918050943 is a deficient number, since it is larger than the sum of its proper divisors (1).

1918050943 is an equidigital number, since it uses as much as digits as its factorization.

1918050943 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 38880, while the sum is 40.

The square root of 1918050943 is about 43795.5584848509. The cubic root of 1918050943 is about 1242.4722924025.

The spelling of 1918050943 in words is "one billion, nine hundred eighteen million, fifty thousand, nine hundred forty-three".