Base | Representation |
---|---|
bin | 111001001010100… |
… | …0100010110110101 |
3 | 11221200021212111221 |
4 | 1302111010112311 |
5 | 12412020003433 |
6 | 514200030341 |
7 | 65350540414 |
oct | 16225042665 |
9 | 4850255457 |
10 | 1918125493 |
11 | 8a4806089 |
12 | 4564623b1 |
13 | 24750b9cb |
14 | 142a6547b |
15 | b35dd72d |
hex | 725445b5 |
1918125493 has 2 divisors, whose sum is σ = 1918125494. Its totient is φ = 1918125492.
The previous prime is 1918125439. The next prime is 1918125533. The reversal of 1918125493 is 3945218191.
Together with previous prime (1918125439) it forms an Ormiston pair, because they use the same digits, order apart.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 1074397284 + 843728209 = 32778^2 + 29047^2 .
It is a cyclic number.
It is not a de Polignac number, because 1918125493 - 221 = 1916028341 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1918125193) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 959062746 + 959062747.
It is an arithmetic number, because the mean of its divisors is an integer number (959062747).
Almost surely, 21918125493 is an apocalyptic number.
It is an amenable number.
1918125493 is a deficient number, since it is larger than the sum of its proper divisors (1).
1918125493 is an equidigital number, since it uses as much as digits as its factorization.
1918125493 is an odious number, because the sum of its binary digits is odd.
The product of its digits is 77760, while the sum is 43.
The square root of 1918125493 is about 43796.4095902849. The cubic root of 1918125493 is about 1242.4883894913.
The spelling of 1918125493 in words is "one billion, nine hundred eighteen million, one hundred twenty-five thousand, four hundred ninety-three".
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