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192540354001 is a prime number
BaseRepresentation
bin1011001101010001001…
…1001010010111010001
3200101222110122101221021
42303110103022113101
511123310312312001
6224241331555441
716624221001642
oct2632423122721
9611873571837
10192540354001
1174724012806
123139545bb81
1315205a1cb68
1494674b56c9
15501d613ba1
hex2cd44ca5d1

192540354001 has 2 divisors, whose sum is σ = 192540354002. Its totient is φ = 192540354000.

The previous prime is 192540353977. The next prime is 192540354073. The reversal of 192540354001 is 100453045291.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 191756410000 + 783944001 = 437900^2 + 27999^2 .

It is an emirp because it is prime and its reverse (100453045291) is a distict prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-192540354001 is a prime.

It is a super-3 number, since 3×1925403540013 (a number of 35 digits) contains 333 as substring.

It is not a weakly prime, because it can be changed into another prime (192540354401) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 96270177000 + 96270177001.

It is an arithmetic number, because the mean of its divisors is an integer number (96270177001).

Almost surely, 2192540354001 is an apocalyptic number.

It is an amenable number.

192540354001 is a deficient number, since it is larger than the sum of its proper divisors (1).

192540354001 is an equidigital number, since it uses as much as digits as its factorization.

192540354001 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 21600, while the sum is 34.

Adding to 192540354001 its reverse (100453045291), we get a palindrome (292993399292).

The spelling of 192540354001 in words is "one hundred ninety-two billion, five hundred forty million, three hundred fifty-four thousand, one".