Base | Representation |
---|---|
bin | 11100010000010010110… |
… | …110000101000001110011 |
3 | 20212121201022210222211202 |
4 | 130100102312011001303 |
5 | 223302440143242201 |
6 | 4043551105201415 |
7 | 260164453311425 |
oct | 34202266050163 |
9 | 6777638728752 |
10 | 1941641384051 |
11 | 689499a40976 |
12 | 27437793026b |
13 | 111132b9c765 |
14 | 69d93dc4815 |
15 | 3578e900c6b |
hex | 1c412d85073 |
1941641384051 has 2 divisors, whose sum is σ = 1941641384052. Its totient is φ = 1941641384050.
The previous prime is 1941641383999. The next prime is 1941641384057. The reversal of 1941641384051 is 1504831461491.
It is a strong prime.
It is an emirp because it is prime and its reverse (1504831461491) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 1941641384051 - 226 = 1941574275187 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 1941641383987 and 1941641384005.
It is not a weakly prime, because it can be changed into another prime (1941641384057) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 970820692025 + 970820692026.
It is an arithmetic number, because the mean of its divisors is an integer number (970820692026).
Almost surely, 21941641384051 is an apocalyptic number.
1941641384051 is a deficient number, since it is larger than the sum of its proper divisors (1).
1941641384051 is an equidigital number, since it uses as much as digits as its factorization.
1941641384051 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 414720, while the sum is 47.
The spelling of 1941641384051 in words is "one trillion, nine hundred forty-one billion, six hundred forty-one million, three hundred eighty-four thousand, fifty-one".
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