Base | Representation |
---|---|
bin | 11100010111010110100… |
… | …001101110011110100001 |
3 | 20220100021110002120110022 |
4 | 130113112201232132201 |
5 | 223414000123203213 |
6 | 4051243051243225 |
7 | 260553321051035 |
oct | 34272641563641 |
9 | 6810243076408 |
10 | 1949219350433 |
11 | 691728564203 |
12 | 275931749515 |
13 | 111a6cb58334 |
14 | 6a4b25d01c5 |
15 | 35a84d34308 |
hex | 1c5d686e7a1 |
1949219350433 has 2 divisors, whose sum is σ = 1949219350434. Its totient is φ = 1949219350432.
The previous prime is 1949219350417. The next prime is 1949219350483. The reversal of 1949219350433 is 3340539129491.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 1539865073569 + 409354276864 = 1240913^2 + 639808^2 .
It is a cyclic number.
It is not a de Polignac number, because 1949219350433 - 24 = 1949219350417 is a prime.
It is a super-2 number, since 2×19492193504332 (a number of 25 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (1949219350483) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 974609675216 + 974609675217.
It is an arithmetic number, because the mean of its divisors is an integer number (974609675217).
Almost surely, 21949219350433 is an apocalyptic number.
It is an amenable number.
1949219350433 is a deficient number, since it is larger than the sum of its proper divisors (1).
1949219350433 is an equidigital number, since it uses as much as digits as its factorization.
1949219350433 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 3149280, while the sum is 53.
The spelling of 1949219350433 in words is "one trillion, nine hundred forty-nine billion, two hundred nineteen million, three hundred fifty thousand, four hundred thirty-three".
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