Base | Representation |
---|---|
bin | 1011010110001100001… |
… | …1111011000111111011 |
3 | 200122011101112111100202 |
4 | 2311203003323013323 |
5 | 11143211442020212 |
6 | 225315132152415 |
7 | 20040453264461 |
oct | 2654303730773 |
9 | 618141474322 |
10 | 194935501307 |
11 | 75743010398 |
12 | 3194360870b |
13 | 154c7cc9aa1 |
14 | 9613630831 |
15 | 510da2c0c2 |
hex | 2d630fb1fb |
194935501307 has 2 divisors, whose sum is σ = 194935501308. Its totient is φ = 194935501306.
The previous prime is 194935501297. The next prime is 194935501333. The reversal of 194935501307 is 703105539491.
It is a weak prime.
It is an emirp because it is prime and its reverse (703105539491) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 194935501307 - 210 = 194935500283 is a prime.
It is a super-2 number, since 2×1949355013072 (a number of 23 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (194935501357) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 97467750653 + 97467750654.
It is an arithmetic number, because the mean of its divisors is an integer number (97467750654).
Almost surely, 2194935501307 is an apocalyptic number.
194935501307 is a deficient number, since it is larger than the sum of its proper divisors (1).
194935501307 is an equidigital number, since it uses as much as digits as its factorization.
194935501307 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 510300, while the sum is 47.
The spelling of 194935501307 in words is "one hundred ninety-four billion, nine hundred thirty-five million, five hundred one thousand, three hundred seven".
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