Base | Representation |
---|---|
bin | 11100011000001001001… |
… | …010101010011100001011 |
3 | 20220102110122202022210222 |
4 | 130120021022222130023 |
5 | 223422220122130403 |
6 | 4051503241100255 |
7 | 260613345343115 |
oct | 34301112523413 |
9 | 6812418668728 |
10 | 1950068942603 |
11 | 6920240973a1 |
12 | 275b2a18768b |
13 | 111b76b82ab2 |
14 | 6a5533883b5 |
15 | 35ad4705338 |
hex | 1c6092aa70b |
1950068942603 has 2 divisors, whose sum is σ = 1950068942604. Its totient is φ = 1950068942602.
The previous prime is 1950068942587. The next prime is 1950068942639. The reversal of 1950068942603 is 3062498600591.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 1950068942603 - 24 = 1950068942587 is a prime.
It is not a weakly prime, because it can be changed into another prime (1950068942663) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 975034471301 + 975034471302.
It is an arithmetic number, because the mean of its divisors is an integer number (975034471302).
Almost surely, 21950068942603 is an apocalyptic number.
1950068942603 is a deficient number, since it is larger than the sum of its proper divisors (1).
1950068942603 is an equidigital number, since it uses as much as digits as its factorization.
1950068942603 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 2799360, while the sum is 53.
The spelling of 1950068942603 in words is "one trillion, nine hundred fifty billion, sixty-eight million, nine hundred forty-two thousand, six hundred three".
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