Search a number
-
+
1950452113 is a prime number
BaseRepresentation
bin111010001000001…
…1000100110010001
312000221010020022011
41310100120212101
512443303431423
6521312542521
766222366211
oct16420304621
95027106264
101950452113
11910a855a5
12465251a41
1325111999c
1414707c241
15b6376b0d
hex74418991

1950452113 has 2 divisors, whose sum is σ = 1950452114. Its totient is φ = 1950452112.

The previous prime is 1950452111. The next prime is 1950452129. The reversal of 1950452113 is 3112540591.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 1662029824 + 288422289 = 40768^2 + 16983^2 .

It is a cyclic number.

It is not a de Polignac number, because 1950452113 - 21 = 1950452111 is a prime.

Together with 1950452111, it forms a pair of twin primes.

It is not a weakly prime, because it can be changed into another prime (1950452111) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 975226056 + 975226057.

It is an arithmetic number, because the mean of its divisors is an integer number (975226057).

Almost surely, 21950452113 is an apocalyptic number.

It is an amenable number.

1950452113 is a deficient number, since it is larger than the sum of its proper divisors (1).

1950452113 is an equidigital number, since it uses as much as digits as its factorization.

1950452113 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 5400, while the sum is 31.

The square root of 1950452113 is about 44163.9232066174. The cubic root of 1950452113 is about 1249.4295237918.

It can be divided in two parts, 19504 and 52113, that added together give a palindrome (71617).

The spelling of 1950452113 in words is "one billion, nine hundred fifty million, four hundred fifty-two thousand, one hundred thirteen".