Search a number
-
+
195168997 is a prime number
BaseRepresentation
bin10111010001000…
…00101011100101
3111121020121112101
423220200223211
5344430401442
631211052101
74556623552
oct1350405345
9447217471
10195168997
11a01933a1
1255441031
133158541a
141bcc5a29
1512202cb7
hexba20ae5

195168997 has 2 divisors, whose sum is σ = 195168998. Its totient is φ = 195168996.

The previous prime is 195168977. The next prime is 195169001. The reversal of 195168997 is 799861591.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 168636196 + 26532801 = 12986^2 + 5151^2 .

It is an emirp because it is prime and its reverse (799861591) is a distict prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-195168997 is a prime.

It is a Chen prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (195168907) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (13) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 97584498 + 97584499.

It is an arithmetic number, because the mean of its divisors is an integer number (97584499).

Almost surely, 2195168997 is an apocalyptic number.

It is an amenable number.

195168997 is a deficient number, since it is larger than the sum of its proper divisors (1).

195168997 is an equidigital number, since it uses as much as digits as its factorization.

195168997 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 1224720, while the sum is 55.

The square root of 195168997 is about 13970.2897965647. The cubic root of 195168997 is about 580.0564719093.

The spelling of 195168997 in words is "one hundred ninety-five million, one hundred sixty-eight thousand, nine hundred ninety-seven".