Search a number
-
+
1953125497 is a prime number
BaseRepresentation
bin111010001101010…
…0101010001111001
312001010011001111101
41310122211101321
513000000003442
6521450131401
766254202301
oct16432452171
95033131441
101953125497
11912541104
12466120b61
1325184477b
14147576601
15b6703cb7
hex746a5479

1953125497 has 2 divisors, whose sum is σ = 1953125498. Its totient is φ = 1953125496.

The previous prime is 1953125491. The next prime is 1953125543. The reversal of 1953125497 is 7945213591.

It is an a-pointer prime, because the next prime (1953125543) can be obtained adding 1953125497 to its sum of digits (46).

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 1283144041 + 669981456 = 35821^2 + 25884^2 .

It is a cyclic number.

It is not a de Polignac number, because 1953125497 - 223 = 1944736889 is a prime.

It is not a weakly prime, because it can be changed into another prime (1953125491) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 976562748 + 976562749.

It is an arithmetic number, because the mean of its divisors is an integer number (976562749).

Almost surely, 21953125497 is an apocalyptic number.

It is an amenable number.

1953125497 is a deficient number, since it is larger than the sum of its proper divisors (1).

1953125497 is an equidigital number, since it uses as much as digits as its factorization.

1953125497 is an evil number, because the sum of its binary digits is even.

The product of its digits is 340200, while the sum is 46.

The square root of 1953125497 is about 44194.1794470720. The cubic root of 1953125497 is about 1250.0001060267. Note that the first 3 decimals are identical.

The spelling of 1953125497 in words is "one billion, nine hundred fifty-three million, one hundred twenty-five thousand, four hundred ninety-seven".