Base | Representation |
---|---|
bin | 1011010111110011011… |
… | …1001100111011011111 |
3 | 200200021120001201001002 |
4 | 2311330313030323133 |
5 | 11200103300431413 |
6 | 225430114140515 |
7 | 20054260531106 |
oct | 2657467147337 |
9 | 620246051032 |
10 | 195368373983 |
11 | 75945399002 |
12 | 31a4458173b |
13 | 155668aaa73 |
14 | 9654d1103d |
15 | 5136a35958 |
hex | 2d7cdccedf |
195368373983 has 2 divisors, whose sum is σ = 195368373984. Its totient is φ = 195368373982.
The previous prime is 195368373979. The next prime is 195368374031. The reversal of 195368373983 is 389373863591.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 195368373983 - 22 = 195368373979 is a prime.
It is a super-4 number, since 4×1953683739834 (a number of 46 digits) contains 4444 as substring. Note that it is a super-d number also for d = 2.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (195368370983) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 97684186991 + 97684186992.
It is an arithmetic number, because the mean of its divisors is an integer number (97684186992).
Almost surely, 2195368373983 is an apocalyptic number.
195368373983 is a deficient number, since it is larger than the sum of its proper divisors (1).
195368373983 is an equidigital number, since it uses as much as digits as its factorization.
195368373983 is an evil number, because the sum of its binary digits is even.
The product of its digits is 88179840, while the sum is 65.
The spelling of 195368373983 in words is "one hundred ninety-five billion, three hundred sixty-eight million, three hundred seventy-three thousand, nine hundred eighty-three".
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