19550443441 has 2 divisors, whose sum is σ = 19550443442. Its totient is φ = 19550443440.

The previous prime is 19550443439. The next prime is 19550443519. The reversal of 19550443441 is 14434405591.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 15531390625 + 4019052816 = 124625^2 + 63396^2 .

It is an emirp because it is prime and its reverse (14434405591) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 19550443441 - 2¹ = 19550443439 is a prime.

Together with 19550443439, it forms a pair of twin primes.

It is a junction number, because it is equal to n+sod(n) for n = 19550443394 and 19550443403.

It is not a weakly prime, because it can be changed into another prime (19550443841) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 9775221720 + 9775221721.

It is an arithmetic number, because the mean of its divisors is an integer number (9775221721).

Almost surely, 2^19550443441 is an apocalyptic number.

It is an amenable number.

19550443441 is a deficient number, since it is larger than the sum of its proper divisors (1).

19550443441 is an equidigital number, since it uses as much as digits as its factorization.

19550443441 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 172800, while the sum is 40.

The spelling of 19550443441 in words is "nineteen billion, five hundred fifty million, four hundred forty-three thousand, four hundred forty-one".