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196124813 is a prime number
BaseRepresentation
bin10111011000010…
…10000010001101
3111200001011122222
423230022002031
5400201443223
631243345125
74601014313
oct1354120215
9450034588
10196124813
11a0786525
12558221a5
133182b4b1
141c0940b3
15123410c8
hexbb0a08d

196124813 has 2 divisors, whose sum is σ = 196124814. Its totient is φ = 196124812.

The previous prime is 196124809. The next prime is 196124833. The reversal of 196124813 is 318421691.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 196084009 + 40804 = 14003^2 + 202^2 .

It is a cyclic number.

It is not a de Polignac number, because 196124813 - 22 = 196124809 is a prime.

It is a Chen prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (196124833) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 98062406 + 98062407.

It is an arithmetic number, because the mean of its divisors is an integer number (98062407).

Almost surely, 2196124813 is an apocalyptic number.

It is an amenable number.

196124813 is a deficient number, since it is larger than the sum of its proper divisors (1).

196124813 is an equidigital number, since it uses as much as digits as its factorization.

196124813 is an evil number, because the sum of its binary digits is even.

The product of its digits is 10368, while the sum is 35.

The square root of 196124813 is about 14004.4568977165. The cubic root of 196124813 is about 581.0018485489.

The spelling of 196124813 in words is "one hundred ninety-six million, one hundred twenty-four thousand, eight hundred thirteen".