Base | Representation |
---|---|
bin | 11100100010110111010… |
… | …101101011111001000011 |
3 | 20221112011221201112220121 |
4 | 130202313111223321003 |
5 | 224114304214033212 |
6 | 4101045440321111 |
7 | 261501543261313 |
oct | 34426725537103 |
9 | 6845157645817 |
10 | 1961581002307 |
11 | 6969a1379223 |
12 | 278201613197 |
13 | 112c8cbc5744 |
14 | 6ad2626d443 |
15 | 3605a1e0d07 |
hex | 1c8b756be43 |
1961581002307 has 2 divisors, whose sum is σ = 1961581002308. Its totient is φ = 1961581002306.
The previous prime is 1961581002301. The next prime is 1961581002313. The reversal of 1961581002307 is 7032001851691.
It is a balanced prime because it is at equal distance from previous prime (1961581002301) and next prime (1961581002313).
It is a cyclic number.
It is not a de Polignac number, because 1961581002307 - 211 = 1961581000259 is a prime.
It is a super-2 number, since 2×19615810023072 (a number of 25 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (1961581002301) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 980790501153 + 980790501154.
It is an arithmetic number, because the mean of its divisors is an integer number (980790501154).
Almost surely, 21961581002307 is an apocalyptic number.
1961581002307 is a deficient number, since it is larger than the sum of its proper divisors (1).
1961581002307 is an equidigital number, since it uses as much as digits as its factorization.
1961581002307 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 90720, while the sum is 43.
Adding to 1961581002307 its reverse (7032001851691), we get a palindrome (8993582853998).
The spelling of 1961581002307 in words is "one trillion, nine hundred sixty-one billion, five hundred eighty-one million, two thousand, three hundred seven".
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