Base | Representation |
---|---|
bin | 1011011011010010010… |
… | …1000001001011001101 |
3 | 200202200200222022001222 |
4 | 2312310211001023031 |
5 | 11204012100200331 |
6 | 230102545213125 |
7 | 20116401041162 |
oct | 2666445011315 |
9 | 622620868058 |
10 | 196303131341 |
11 | 76285000049 |
12 | 320656311a5 |
13 | 15685453925 |
14 | 9703118069 |
15 | 518db2ab7b |
hex | 2db49412cd |
196303131341 has 2 divisors, whose sum is σ = 196303131342. Its totient is φ = 196303131340.
The previous prime is 196303131281. The next prime is 196303131359. The reversal of 196303131341 is 143131303691.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 194264970025 + 2038161316 = 440755^2 + 45146^2 .
It is an emirp because it is prime and its reverse (143131303691) is a distict prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-196303131341 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (196303131371) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 98151565670 + 98151565671.
It is an arithmetic number, because the mean of its divisors is an integer number (98151565671).
Almost surely, 2196303131341 is an apocalyptic number.
It is an amenable number.
196303131341 is a deficient number, since it is larger than the sum of its proper divisors (1).
196303131341 is an equidigital number, since it uses as much as digits as its factorization.
196303131341 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 17496, while the sum is 35.
The spelling of 196303131341 in words is "one hundred ninety-six billion, three hundred three million, one hundred thirty-one thousand, three hundred forty-one".
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