Base | Representation |
---|---|
bin | 10010010100100101… |
… | …000000011110001011 |
3 | 1212210000110112200222 |
4 | 102110211000132023 |
5 | 310242141122121 |
6 | 13012032020255 |
7 | 1264335220214 |
oct | 222445003613 |
9 | 55700415628 |
10 | 19672598411 |
11 | 838573a3a4 |
12 | 399039168b |
13 | 1b1690479b |
14 | d48a1c40b |
15 | 7a21480ab |
hex | 49494078b |
19672598411 has 2 divisors, whose sum is σ = 19672598412. Its totient is φ = 19672598410.
The previous prime is 19672598371. The next prime is 19672598467. The reversal of 19672598411 is 11489527691.
It is a weak prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-19672598411 is a prime.
It is a super-2 number, since 2×196725984112 (a number of 21 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (19672598111) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 9836299205 + 9836299206.
It is an arithmetic number, because the mean of its divisors is an integer number (9836299206).
Almost surely, 219672598411 is an apocalyptic number.
19672598411 is a deficient number, since it is larger than the sum of its proper divisors (1).
19672598411 is an equidigital number, since it uses as much as digits as its factorization.
19672598411 is an evil number, because the sum of its binary digits is even.
The product of its digits is 1088640, while the sum is 53.
The spelling of 19672598411 in words is "nineteen billion, six hundred seventy-two million, five hundred ninety-eight thousand, four hundred eleven".
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