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1968036068981 is a prime number
BaseRepresentation
bin11100101000111000000…
…101110011111001110101
320222010211211001220201002
4130220320011303321311
5224221014213201411
64104034151013045
7262120524400553
oct34507005637165
96863754056632
101968036068981
11699704066374
1227950336a185
1311377b343418
146b379698bd3
15362d6c6833b
hex1ca38173e75

1968036068981 has 2 divisors, whose sum is σ = 1968036068982. Its totient is φ = 1968036068980.

The previous prime is 1968036068951. The next prime is 1968036069001. The reversal of 1968036068981 is 1898606308691.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 1112531314756 + 855504754225 = 1054766^2 + 924935^2 .

It is a cyclic number.

It is not a de Polignac number, because 1968036068981 - 26 = 1968036068917 is a prime.

It is a super-3 number, since 3×19680360689813 (a number of 38 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1968036068951) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 984018034490 + 984018034491.

It is an arithmetic number, because the mean of its divisors is an integer number (984018034491).

Almost surely, 21968036068981 is an apocalyptic number.

It is an amenable number.

1968036068981 is a deficient number, since it is larger than the sum of its proper divisors (1).

1968036068981 is an equidigital number, since it uses as much as digits as its factorization.

1968036068981 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 26873856, while the sum is 65.

The spelling of 1968036068981 in words is "one trillion, nine hundred sixty-eight billion, thirty-six million, sixty-eight thousand, nine hundred eighty-one".