Base | Representation |
---|---|
bin | 111010101010000… |
… | …1011111101010101 |
3 | 12002011120020200012 |
4 | 1311110023331111 |
5 | 13012331214013 |
6 | 523145530005 |
7 | 66526434416 |
oct | 16524137525 |
9 | 5064506605 |
10 | 1968226133 |
11 | 920015475 |
12 | 46b1a3905 |
13 | 254a00b63 |
14 | 14958780d |
15 | b7bd81a8 |
hex | 7550bf55 |
1968226133 has 2 divisors, whose sum is σ = 1968226134. Its totient is φ = 1968226132.
The previous prime is 1968226129. The next prime is 1968226147. The reversal of 1968226133 is 3316228691.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 1908117124 + 60109009 = 43682^2 + 7753^2 .
It is an emirp because it is prime and its reverse (3316228691) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 1968226133 - 22 = 1968226129 is a prime.
It is a super-2 number, since 2×19682261332 = 7747828221248267378, which contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1968226123) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 984113066 + 984113067.
It is an arithmetic number, because the mean of its divisors is an integer number (984113067).
Almost surely, 21968226133 is an apocalyptic number.
It is an amenable number.
1968226133 is a deficient number, since it is larger than the sum of its proper divisors (1).
1968226133 is an equidigital number, since it uses as much as digits as its factorization.
1968226133 is an evil number, because the sum of its binary digits is even.
The product of its digits is 93312, while the sum is 41.
The square root of 1968226133 is about 44364.6946681705. The cubic root of 1968226133 is about 1253.2133076849.
The spelling of 1968226133 in words is "one billion, nine hundred sixty-eight million, two hundred twenty-six thousand, one hundred thirty-three".
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