Base | Representation |
---|---|
bin | 11100101001101111001… |
… | …110001100011011101011 |
3 | 20222020020021111222000212 |
4 | 130221233032030123223 |
5 | 224224413004412413 |
6 | 4104310031451335 |
7 | 262152455321012 |
oct | 34515716143353 |
9 | 6866207458025 |
10 | 1968961013483 |
11 | 69a039185912 |
12 | 279721086b4b |
13 | 113897b61969 |
14 | 6b426469a79 |
15 | 3633d070ca8 |
hex | 1ca6f38c6eb |
1968961013483 has 2 divisors, whose sum is σ = 1968961013484. Its totient is φ = 1968961013482.
The previous prime is 1968961013417. The next prime is 1968961013587. The reversal of 1968961013483 is 3843101698691.
It is a weak prime.
It is an emirp because it is prime and its reverse (3843101698691) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 1968961013483 - 214 = 1968960997099 is a prime.
It is not a weakly prime, because it can be changed into another prime (1968961018483) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 984480506741 + 984480506742.
It is an arithmetic number, because the mean of its divisors is an integer number (984480506742).
Almost surely, 21968961013483 is an apocalyptic number.
1968961013483 is a deficient number, since it is larger than the sum of its proper divisors (1).
1968961013483 is an equidigital number, since it uses as much as digits as its factorization.
1968961013483 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 6718464, while the sum is 59.
The spelling of 1968961013483 in words is "one trillion, nine hundred sixty-eight billion, nine hundred sixty-one million, thirteen thousand, four hundred eighty-three".
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