Base | Representation |
---|---|
bin | 11100101001101111001… |
… | …110001101101001110011 |
3 | 20222020020021112012220001 |
4 | 130221233032031221303 |
5 | 224224413010042413 |
6 | 4104310031530431 |
7 | 262152455341414 |
oct | 34515716155163 |
9 | 6866207465801 |
10 | 1968961018483 |
11 | 69a039189648 |
12 | 279721089a17 |
13 | 113897b64014 |
14 | 6b42646b80b |
15 | 3633d0724dd |
hex | 1ca6f38da73 |
1968961018483 has 2 divisors, whose sum is σ = 1968961018484. Its totient is φ = 1968961018482.
The previous prime is 1968961018481. The next prime is 1968961018517. The reversal of 1968961018483 is 3848101698691.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 1968961018483 - 21 = 1968961018481 is a prime.
It is a super-2 number, since 2×19689610184832 (a number of 25 digits) contains 22 as substring.
Together with 1968961018481, it forms a pair of twin primes.
It is not a weakly prime, because it can be changed into another prime (1968961018481) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 984480509241 + 984480509242.
It is an arithmetic number, because the mean of its divisors is an integer number (984480509242).
Almost surely, 21968961018483 is an apocalyptic number.
1968961018483 is a deficient number, since it is larger than the sum of its proper divisors (1).
1968961018483 is an equidigital number, since it uses as much as digits as its factorization.
1968961018483 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 17915904, while the sum is 64.
The spelling of 1968961018483 in words is "one trillion, nine hundred sixty-eight billion, nine hundred sixty-one million, eighteen thousand, four hundred eighty-three".
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