Base | Representation |
---|---|
bin | 101100110100001110011011… |
… | …101000101101011001001111 |
3 | 221211212212011211221222112001 |
4 | 230310032123220231121033 |
5 | 201313313323030232121 |
6 | 1535111503031453131 |
7 | 56342134655665033 |
oct | 5464163350553117 |
9 | 854785154858461 |
10 | 197102955320911 |
11 | 578919918a7052 |
12 | 1a133a58b271a7 |
13 | 85c996260b713 |
14 | 3695b964841c3 |
15 | 17bc178250991 |
hex | b3439ba2d64f |
197102955320911 has 2 divisors, whose sum is σ = 197102955320912. Its totient is φ = 197102955320910.
The previous prime is 197102955320879. The next prime is 197102955320951. The reversal of 197102955320911 is 119023559201791.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 197102955320911 - 25 = 197102955320879 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (197102955320951) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 98551477660455 + 98551477660456.
It is an arithmetic number, because the mean of its divisors is an integer number (98551477660456).
Almost surely, 2197102955320911 is an apocalyptic number.
197102955320911 is a deficient number, since it is larger than the sum of its proper divisors (1).
197102955320911 is an equidigital number, since it uses as much as digits as its factorization.
197102955320911 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 1530900, while the sum is 55.
The spelling of 197102955320911 in words is "one hundred ninety-seven trillion, one hundred two billion, nine hundred fifty-five million, three hundred twenty thousand, nine hundred eleven".
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