Base | Representation |
---|---|
bin | 10010010110111000… |
… | …101110000110000001 |
3 | 1212212201022211100112 |
4 | 102112320232012001 |
5 | 310332044223244 |
6 | 13015534001105 |
7 | 1265315313362 |
oct | 222670560601 |
9 | 55781284315 |
10 | 19711320449 |
11 | 83a5587887 |
12 | 39a1346195 |
13 | 1b21941732 |
14 | d4dc1bb69 |
15 | 7a574639e |
hex | 496e2e181 |
19711320449 has 2 divisors, whose sum is σ = 19711320450. Its totient is φ = 19711320448.
The previous prime is 19711320403. The next prime is 19711320451. The reversal of 19711320449 is 94402311791.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 14265913600 + 5445406849 = 119440^2 + 73793^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-19711320449 is a prime.
Together with 19711320451, it forms a pair of twin primes.
It is a Chen prime.
It is not a weakly prime, because it can be changed into another prime (19711320469) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 9855660224 + 9855660225.
It is an arithmetic number, because the mean of its divisors is an integer number (9855660225).
Almost surely, 219711320449 is an apocalyptic number.
It is an amenable number.
19711320449 is a deficient number, since it is larger than the sum of its proper divisors (1).
19711320449 is an equidigital number, since it uses as much as digits as its factorization.
19711320449 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 54432, while the sum is 41.
The spelling of 19711320449 in words is "nineteen billion, seven hundred eleven million, three hundred twenty thousand, four hundred forty-nine".
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