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19712293553 is a prime number
BaseRepresentation
bin10010010110111100…
…011011101010110001
31212212210011021012102
4102112330123222301
5310332321343203
613020010510145
71265326505411
oct222674335261
955783137172
1019712293553
1183a60919a7
1239a1735355
131b21bc2634
14d4ddd2641
157a5889888
hex496f1bab1

19712293553 has 2 divisors, whose sum is σ = 19712293554. Its totient is φ = 19712293552.

The previous prime is 19712293541. The next prime is 19712293561. The reversal of 19712293553 is 35539221791.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 16577077504 + 3135216049 = 128752^2 + 55993^2 .

It is an emirp because it is prime and its reverse (35539221791) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 19712293553 - 216 = 19712228017 is a prime.

It is a Sophie Germain prime.

It is a Curzon number.

It is a junction number, because it is equal to n+sod(n) for n = 19712293498 and 19712293507.

It is not a weakly prime, because it can be changed into another prime (19712293583) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 9856146776 + 9856146777.

It is an arithmetic number, because the mean of its divisors is an integer number (9856146777).

Almost surely, 219712293553 is an apocalyptic number.

It is an amenable number.

19712293553 is a deficient number, since it is larger than the sum of its proper divisors (1).

19712293553 is an equidigital number, since it uses as much as digits as its factorization.

19712293553 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 510300, while the sum is 47.

The spelling of 19712293553 in words is "nineteen billion, seven hundred twelve million, two hundred ninety-three thousand, five hundred fifty-three".