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197132633250 = 2353717191011151
BaseRepresentation
bin1011011110011000000…
…1010100010010100010
3200211211111211100202220
42313212001110102202
511212211423231000
6230321140251510
720146062510120
oct2674601242242
9624744740686
10197132633250
1176670261113
12322573a0b96
1315788265b67
149781362910
1551db87e1a0
hex2de60544a2

197132633250 has 512 divisors, whose sum is σ = 633506365440. Its totient is φ = 39744000000.

The previous prime is 197132633239. The next prime is 197132633317. The reversal of 197132633250 is 52336231791.

It is a super-2 number, since 2×1971326332502 (a number of 23 digits) contains 22 as substring.

It is a Harshad number since it is a multiple of its sum of digits (42).

It is a Curzon number.

It is an unprimeable number.

It is a polite number, since it can be written in 255 ways as a sum of consecutive naturals, for example, 171270175 + ... + 171271325.

It is an arithmetic number, because the mean of its divisors is an integer number (1237317120).

Almost surely, 2197132633250 is an apocalyptic number.

197132633250 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is a practical number, because each smaller number is the sum of distinct divisors of 197132633250, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (316753182720).

197132633250 is an abundant number, since it is smaller than the sum of its proper divisors (436373732190).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

197132633250 is a wasteful number, since it uses less digits than its factorization.

197132633250 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 1315 (or 1305 counting only the distinct ones).

The product of its (nonzero) digits is 204120, while the sum is 42.

The spelling of 197132633250 in words is "one hundred ninety-seven billion, one hundred thirty-two million, six hundred thirty-three thousand, two hundred fifty".