Base | Representation |
---|---|
bin | 11100101101110111110… |
… | …111011000000000000001 |
3 | 20222122200201010100000001 |
4 | 130231313313120000001 |
5 | 224313011123300133 |
6 | 4110322400000001 |
7 | 262400500453015 |
oct | 34556767300001 |
9 | 6878621110001 |
10 | 1973400993793 |
11 | 6a0a07461829 |
12 | 27a560000001 |
13 | 114124982548 |
14 | 6b727dd0545 |
15 | 364ecc5587d |
hex | 1cb77dd8001 |
1973400993793 has 2 divisors, whose sum is σ = 1973400993794. Its totient is φ = 1973400993792.
The previous prime is 1973400993787. The next prime is 1973400993797. The reversal of 1973400993793 is 3973990043791.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 1972698902784 + 702091009 = 1404528^2 + 26497^2 .
It is a cyclic number.
It is not a de Polignac number, because 1973400993793 - 29 = 1973400993281 is a prime.
It is a super-2 number, since 2×19734009937932 (a number of 25 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (1973400993797) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 986700496896 + 986700496897.
It is an arithmetic number, because the mean of its divisors is an integer number (986700496897).
Almost surely, 21973400993793 is an apocalyptic number.
It is an amenable number.
1973400993793 is a deficient number, since it is larger than the sum of its proper divisors (1).
1973400993793 is an equidigital number, since it uses as much as digits as its factorization.
1973400993793 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 34720812, while the sum is 64.
The spelling of 1973400993793 in words is "one trillion, nine hundred seventy-three billion, four hundred million, nine hundred ninety-three thousand, seven hundred ninety-three".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.089 sec. • engine limits •