Base | Representation |
---|---|
bin | 10010011001000110… |
… | …001001110100000101 |
3 | 1212222022002110211221 |
4 | 102121012021310011 |
5 | 310421042140133 |
6 | 13023340400341 |
7 | 1266245412253 |
oct | 223106116405 |
9 | 55868073757 |
10 | 19748396293 |
11 | 841450047a |
12 | 39b18460b1 |
13 | 1b295232c2 |
14 | d54b0d5d3 |
15 | 7a8b1ba2d |
hex | 499189d05 |
19748396293 has 2 divisors, whose sum is σ = 19748396294. Its totient is φ = 19748396292.
The previous prime is 19748396267. The next prime is 19748396347. The reversal of 19748396293 is 39269384791.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 19415078244 + 333318049 = 139338^2 + 18257^2 .
It is a cyclic number.
It is not a de Polignac number, because 19748396293 - 233 = 11158461701 is a prime.
It is a super-2 number, since 2×197483962932 (a number of 21 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (19748396203) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 9874198146 + 9874198147.
It is an arithmetic number, because the mean of its divisors is an integer number (9874198147).
Almost surely, 219748396293 is an apocalyptic number.
It is an amenable number.
19748396293 is a deficient number, since it is larger than the sum of its proper divisors (1).
19748396293 is an equidigital number, since it uses as much as digits as its factorization.
19748396293 is an evil number, because the sum of its binary digits is even.
The product of its digits is 17635968, while the sum is 61.
The spelling of 19748396293 in words is "nineteen billion, seven hundred forty-eight million, three hundred ninety-six thousand, two hundred ninety-three".
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