Base | Representation |
---|---|
bin | 11100101111011010101… |
… | …101101101111111011101 |
3 | 20222210222021201102222111 |
4 | 130233122231231333131 |
5 | 224324410202004223 |
6 | 4111155121314021 |
7 | 262456545650263 |
oct | 34573255557735 |
9 | 6883867642874 |
10 | 1975059406813 |
11 | 6a16885aaaa9 |
12 | 27a943495911 |
13 | 11432a42ab1c |
14 | 6b84436c433 |
15 | 3659864230d |
hex | 1cbdab6dfdd |
1975059406813 has 2 divisors, whose sum is σ = 1975059406814. Its totient is φ = 1975059406812.
The previous prime is 1975059406781. The next prime is 1975059406867. The reversal of 1975059406813 is 3186049505791.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 1225444572004 + 749614834809 = 1106998^2 + 865803^2 .
It is an emirp because it is prime and its reverse (3186049505791) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 1975059406813 - 25 = 1975059406781 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1975059406883) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (29) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 987529703406 + 987529703407.
It is an arithmetic number, because the mean of its divisors is an integer number (987529703407).
Almost surely, 21975059406813 is an apocalyptic number.
It is an amenable number.
1975059406813 is a deficient number, since it is larger than the sum of its proper divisors (1).
1975059406813 is an equidigital number, since it uses as much as digits as its factorization.
1975059406813 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 8164800, while the sum is 58.
The spelling of 1975059406813 in words is "one trillion, nine hundred seventy-five billion, fifty-nine million, four hundred six thousand, eight hundred thirteen".
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