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197512813397 is a prime number
BaseRepresentation
bin1011011111110010101…
…1100101101101010101
3200212211000012111220002
42313330223211231111
511214001240012042
6230423001021045
720161360133054
oct2677453455525
9625730174802
10197512813397
117684591a089
1232342784785
1315818c58023
1497b9a4839b
15520ee2a132
hex2dfcae5b55

197512813397 has 2 divisors, whose sum is σ = 197512813398. Its totient is φ = 197512813396.

The previous prime is 197512813373. The next prime is 197512813403. The reversal of 197512813397 is 793318215791.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 101384291281 + 96128522116 = 318409^2 + 310046^2 .

It is an emirp because it is prime and its reverse (793318215791) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 197512813397 - 210 = 197512812373 is a prime.

It is a super-2 number, since 2×1975128133972 (a number of 23 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (197512813357) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 98756406698 + 98756406699.

It is an arithmetic number, because the mean of its divisors is an integer number (98756406699).

Almost surely, 2197512813397 is an apocalyptic number.

It is an amenable number.

197512813397 is a deficient number, since it is larger than the sum of its proper divisors (1).

197512813397 is an equidigital number, since it uses as much as digits as its factorization.

197512813397 is an evil number, because the sum of its binary digits is even.

The product of its digits is 2857680, while the sum is 56.

The spelling of 197512813397 in words is "one hundred ninety-seven billion, five hundred twelve million, eight hundred thirteen thousand, three hundred ninety-seven".