Base | Representation |
---|---|
bin | 11100110100010101010… |
… | …000000001011000001111 |
3 | 21000022121001101202102011 |
4 | 130310111100001120033 |
5 | 224421212112214233 |
6 | 4113430510442051 |
7 | 263034404021143 |
oct | 34642520013017 |
9 | 7008531352364 |
10 | 1980336444943 |
11 | 6a394632893a |
12 | 27b976803327 |
13 | 11498b7a7bac |
14 | 6bbc5147223 |
15 | 367a6a6e0cd |
hex | 1cd1540160f |
1980336444943 has 2 divisors, whose sum is σ = 1980336444944. Its totient is φ = 1980336444942.
The previous prime is 1980336444907. The next prime is 1980336445027. The reversal of 1980336444943 is 3494446330891.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 1980336444943 - 213 = 1980336436751 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1980336414943) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 990168222471 + 990168222472.
It is an arithmetic number, because the mean of its divisors is an integer number (990168222472).
Almost surely, 21980336444943 is an apocalyptic number.
1980336444943 is a deficient number, since it is larger than the sum of its proper divisors (1).
1980336444943 is an equidigital number, since it uses as much as digits as its factorization.
1980336444943 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 26873856, while the sum is 58.
The spelling of 1980336444943 in words is "one trillion, nine hundred eighty billion, three hundred thirty-six million, four hundred forty-four thousand, nine hundred forty-three".
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