Base | Representation |
---|---|
bin | 1011100010000010000… |
… | …1110010101101011000 |
3 | 200221100220212101111022 |
4 | 2320200201302231120 |
5 | 11221214220144414 |
6 | 231002403222012 |
7 | 20212312061444 |
oct | 2704041625530 |
9 | 627326771438 |
10 | 198114224984 |
11 | 77024351555 |
12 | 32490077908 |
13 | 158b3729280 |
14 | 983587b824 |
15 | 5247b2618e |
hex | 2e20872b58 |
198114224984 has 16 divisors (see below), whose sum is σ = 400038339120. Its totient is φ = 91437334560.
The previous prime is 198114224927. The next prime is 198114224999. The reversal of 198114224984 is 489422411891.
It is a super-2 number, since 2×1981142249842 (a number of 23 digits) contains 22 as substring.
It is a Smith number, since the sum of its digits (53) coincides with the sum of the digits of its prime factors.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 952472132 + ... + 952472339.
It is an arithmetic number, because the mean of its divisors is an integer number (25002396195).
Almost surely, 2198114224984 is an apocalyptic number.
It is an amenable number.
198114224984 is an abundant number, since it is smaller than the sum of its proper divisors (201924114136).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
198114224984 is a wasteful number, since it uses less digits than its factorization.
198114224984 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 1904944490 (or 1904944486 counting only the distinct ones).
The product of its digits is 1327104, while the sum is 53.
The spelling of 198114224984 in words is "one hundred ninety-eight billion, one hundred fourteen million, two hundred twenty-four thousand, nine hundred eighty-four".
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