19812453901 has 2 divisors, whose sum is σ = 19812453902. Its totient is φ = 19812453900.

The previous prime is 19812453847. The next prime is 19812453929. The reversal of 19812453901 is 10935421891.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 16294777801 + 3517676100 = 127651^2 + 59310^2 .

It is a cyclic number.

It is not a de Polignac number, because 19812453901 - 2⁹ = 19812453389 is a prime.

It is a super-3 number, since 3×19812453901³ (a number of 32 digits) contains 333 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (19812453971) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 9906226950 + 9906226951.

It is an arithmetic number, because the mean of its divisors is an integer number (9906226951).

Almost surely, 2^19812453901 is an apocalyptic number.

It is an amenable number.

19812453901 is a deficient number, since it is larger than the sum of its proper divisors (1).

19812453901 is an equidigital number, since it uses as much as digits as its factorization.

19812453901 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 77760, while the sum is 43.

The spelling of 19812453901 in words is "nineteen billion, eight hundred twelve million, four hundred fifty-three thousand, nine hundred one".