Base | Representation |
---|---|
bin | 10010011100111100… |
… | …110011100011001110 |
3 | 1220010210202110110122 |
4 | 102130330303203032 |
5 | 311034120222140 |
6 | 13034010304542 |
7 | 1300662120533 |
oct | 223474634316 |
9 | 56123673418 |
10 | 19813054670 |
11 | 8447a53252 |
12 | 3a0b428152 |
13 | 1b39a416b6 |
14 | d5d540d8a |
15 | 7ae63eab5 |
hex | 49cf338ce |
19813054670 has 16 divisors (see below), whose sum is σ = 35673702048. Its totient is φ = 7922954400.
The previous prime is 19813054661. The next prime is 19813054673. The reversal of 19813054670 is 7645031891.
It is a super-3 number, since 3×198130546703 (a number of 32 digits) contains 333 as substring.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (19813054673) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 246506 + ... + 316845.
It is an arithmetic number, because the mean of its divisors is an integer number (2229606378).
Almost surely, 219813054670 is an apocalyptic number.
19813054670 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
19813054670 is a deficient number, since it is larger than the sum of its proper divisors (15860647378).
19813054670 is a wasteful number, since it uses less digits than its factorization.
19813054670 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 566875.
The product of its (nonzero) digits is 181440, while the sum is 44.
The spelling of 19813054670 in words is "nineteen billion, eight hundred thirteen million, fifty-four thousand, six hundred seventy".
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