Base | Representation |
---|---|
bin | 10010011100111100… |
… | …110101101010010001 |
3 | 1220010210202220022202 |
4 | 102130330311222101 |
5 | 311034121011223 |
6 | 13034010412545 |
7 | 1300662154661 |
oct | 223474655221 |
9 | 56123686282 |
10 | 19813063313 |
11 | 8447a5979a |
12 | 3a0b431155 |
13 | 1b39a45604 |
14 | d5d5441a1 |
15 | 7ae642428 |
hex | 49cf35a91 |
19813063313 has 2 divisors, whose sum is σ = 19813063314. Its totient is φ = 19813063312.
The previous prime is 19813063279. The next prime is 19813063339. The reversal of 19813063313 is 31336031891.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 19216336129 + 596727184 = 138623^2 + 24428^2 .
It is an emirp because it is prime and its reverse (31336031891) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 19813063313 - 28 = 19813063057 is a prime.
It is a super-3 number, since 3×198130633133 (a number of 32 digits) contains 333 as substring.
It is not a weakly prime, because it can be changed into another prime (19813063343) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 9906531656 + 9906531657.
It is an arithmetic number, because the mean of its divisors is an integer number (9906531657).
Almost surely, 219813063313 is an apocalyptic number.
It is an amenable number.
19813063313 is a deficient number, since it is larger than the sum of its proper divisors (1).
19813063313 is an equidigital number, since it uses as much as digits as its factorization.
19813063313 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 34992, while the sum is 38.
The spelling of 19813063313 in words is "nineteen billion, eight hundred thirteen million, sixty-three thousand, three hundred thirteen".
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