Base | Representation |
---|---|
bin | 10010011100111100… |
… | …111101101001011111 |
3 | 1220010210211120012112 |
4 | 102130330331221133 |
5 | 311034123033111 |
6 | 13034011224235 |
7 | 1300662352241 |
oct | 223474755137 |
9 | 56123746175 |
10 | 19813096031 |
11 | 8447a81333 |
12 | 3a0b44807b |
13 | 1b39a57481 |
14 | d5d552091 |
15 | 7ae64be8b |
hex | 49cf3da5f |
19813096031 has 2 divisors, whose sum is σ = 19813096032. Its totient is φ = 19813096030.
The previous prime is 19813096027. The next prime is 19813096087. The reversal of 19813096031 is 13069031891.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 19813096031 - 22 = 19813096027 is a prime.
It is a super-3 number, since 3×198130960313 (a number of 32 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.
It is a self number, because there is not a number n which added to its sum of digits gives 19813096031.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (19813096531) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 9906548015 + 9906548016.
It is an arithmetic number, because the mean of its divisors is an integer number (9906548016).
Almost surely, 219813096031 is an apocalyptic number.
19813096031 is a deficient number, since it is larger than the sum of its proper divisors (1).
19813096031 is an equidigital number, since it uses as much as digits as its factorization.
19813096031 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 34992, while the sum is 41.
The spelling of 19813096031 in words is "nineteen billion, eight hundred thirteen million, ninety-six thousand, thirty-one".
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