1981413103 has 2 divisors, whose sum is σ = 1981413104. Its totient is φ = 1981413102.

The previous prime is 1981413079. The next prime is 1981413149. The reversal of 1981413103 is 3013141891.

It is a weak prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-1981413103 is a prime.

It is a super-3 number, since 3×1981413103³ (a number of 29 digits) contains 333 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1981413173) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 990706551 + 990706552.

It is an arithmetic number, because the mean of its divisors is an integer number (990706552).

Almost surely, 2^1981413103 is an apocalyptic number.

1981413103 is a deficient number, since it is larger than the sum of its proper divisors (1).

1981413103 is an equidigital number, since it uses as much as digits as its factorization.

1981413103 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 2592, while the sum is 31.

The square root of 1981413103 is about 44513.0666546352. The cubic root of 1981413103 is about 1256.0058924950.

Adding to 1981413103 its reverse (3013141891), we get a palindrome (4994554994).

The spelling of 1981413103 in words is "one billion, nine hundred eighty-one million, four hundred thirteen thousand, one hundred three".