1981498982400 has 1632 divisors, whose sum is σ = 8529471539200. Its totient is φ = 447180963840.

The previous prime is 1981498982377. The next prime is 1981498982429. The reversal of 1981498982400 is 42898941891.

1981498982400 is a `hidden beast` number, since 1 + 9 + 8 + 149 + 8 + 9 + 82 + 400 = 666.

It is a Harshad number since it is a multiple of its sum of digits (63).

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written in 95 ways as a sum of consecutive naturals, for example, 25082265561 + ... + 25082265639.

Almost surely, 2^{1981498982400} is an apocalyptic number.

1981498982400 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 1981498982400, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (4264735769600).

1981498982400 is an abundant number, since it is smaller than the sum of its proper divisors (6547972556800).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

1981498982400 is an frugal number, since it uses more digits than its factorization.

1981498982400 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 149 (or 96 counting only the distinct ones).

The product of its (nonzero) digits is 11943936, while the sum is 63.

The spelling of 1981498982400 in words is "one trillion, nine hundred eighty-one billion, four hundred ninety-eight million, nine hundred eighty-two thousand, four hundred".