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198155933 is a prime number
BaseRepresentation
bin10111100111110…
…01111010011101
3111210212100211122
423303321322131
5401211442213
631355100325
74624204043
oct1363717235
9453770748
10198155933
11a1943538
12564416a5
133208cb41
141c462393
15125e2d08
hexbcf9e9d

198155933 has 2 divisors, whose sum is σ = 198155934. Its totient is φ = 198155932.

The previous prime is 198155899. The next prime is 198155953. The reversal of 198155933 is 339551891.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 197486809 + 669124 = 14053^2 + 818^2 .

It is a cyclic number.

It is not a de Polignac number, because 198155933 - 210 = 198154909 is a prime.

It is a Chen prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (198155953) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 99077966 + 99077967.

It is an arithmetic number, because the mean of its divisors is an integer number (99077967).

Almost surely, 2198155933 is an apocalyptic number.

It is an amenable number.

198155933 is a deficient number, since it is larger than the sum of its proper divisors (1).

198155933 is an equidigital number, since it uses as much as digits as its factorization.

198155933 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 145800, while the sum is 44.

The square root of 198155933 is about 14076.7870268751. The cubic root of 198155933 is about 583.0006335395. Note that the first 3 decimals are identical.

The spelling of 198155933 in words is "one hundred ninety-eight million, one hundred fifty-five thousand, nine hundred thirty-three".