Base | Representation |
---|---|
bin | 11100110101100110111… |
… | …100011001000101001011 |
3 | 21000110010120101201211111 |
4 | 130311212330121011023 |
5 | 224432013444441414 |
6 | 4114214511111151 |
7 | 263113355555353 |
oct | 34654674310513 |
9 | 7013116351744 |
10 | 1981707030859 |
11 | 6a4489a57376 |
12 | 2800998124b7 |
13 | 114b4972828a |
14 | 6bcb519db63 |
15 | 368370538c4 |
hex | 1cd66f1914b |
1981707030859 has 2 divisors, whose sum is σ = 1981707030860. Its totient is φ = 1981707030858.
The previous prime is 1981707030847. The next prime is 1981707030917. The reversal of 1981707030859 is 9580307071891.
It is an a-pointer prime, because the next prime (1981707030917) can be obtained adding 1981707030859 to its sum of digits (58).
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 1981707030859 - 217 = 1981706899787 is a prime.
It is not a weakly prime, because it can be changed into another prime (1981707031859) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 990853515429 + 990853515430.
It is an arithmetic number, because the mean of its divisors is an integer number (990853515430).
Almost surely, 21981707030859 is an apocalyptic number.
1981707030859 is a deficient number, since it is larger than the sum of its proper divisors (1).
1981707030859 is an equidigital number, since it uses as much as digits as its factorization.
1981707030859 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 3810240, while the sum is 58.
The spelling of 1981707030859 in words is "one trillion, nine hundred eighty-one billion, seven hundred seven million, thirty thousand, eight hundred fifty-nine".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.067 sec. • engine limits •