Base | Representation |
---|---|
bin | 11100110110001010000… |
… | …111011100001110101111 |
3 | 21000111122200202212112122 |
4 | 130312022013130032233 |
5 | 224434221031124103 |
6 | 4114353231023155 |
7 | 263134112406626 |
oct | 34661207341657 |
9 | 7014580685478 |
10 | 1982297129903 |
11 | 6a4762062532 |
12 | 28022336aabb |
13 | 114c11a683cc |
14 | 6bd2d6ca6bd |
15 | 3686dc67b38 |
hex | 1cd8a1dc3af |
1982297129903 has 2 divisors, whose sum is σ = 1982297129904. Its totient is φ = 1982297129902.
The previous prime is 1982297129887. The next prime is 1982297129941. The reversal of 1982297129903 is 3099217922891.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 1982297129903 - 24 = 1982297129887 is a prime.
It is a super-2 number, since 2×19822971299032 (a number of 25 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1982297129983) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 991148564951 + 991148564952.
It is an arithmetic number, because the mean of its divisors is an integer number (991148564952).
Almost surely, 21982297129903 is an apocalyptic number.
1982297129903 is a deficient number, since it is larger than the sum of its proper divisors (1).
1982297129903 is an equidigital number, since it uses as much as digits as its factorization.
1982297129903 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 8817984, while the sum is 62.
The spelling of 1982297129903 in words is "one trillion, nine hundred eighty-two billion, two hundred ninety-seven million, one hundred twenty-nine thousand, nine hundred three".
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