Base | Representation |
---|---|
bin | 1011100010110001010… |
… | …0010000110100011001 |
3 | 200221212201000122111222 |
4 | 2320230110100310121 |
5 | 11222120333124024 |
6 | 231034150301425 |
7 | 20220233141315 |
oct | 2705424206431 |
9 | 627781018458 |
10 | 198312004889 |
11 | 77115a58519 |
12 | 32526357875 |
13 | 159156b6bbb |
14 | 9853c42b45 |
15 | 525a19285e |
hex | 2e2c510d19 |
198312004889 has 2 divisors, whose sum is σ = 198312004890. Its totient is φ = 198312004888.
The previous prime is 198312004789. The next prime is 198312004903. The reversal of 198312004889 is 988400213891.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 145500288025 + 52811716864 = 381445^2 + 229808^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-198312004889 is a prime.
It is a self number, because there is not a number n which added to its sum of digits gives 198312004889.
It is not a weakly prime, because it can be changed into another prime (198312004789) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 99156002444 + 99156002445.
It is an arithmetic number, because the mean of its divisors is an integer number (99156002445).
Almost surely, 2198312004889 is an apocalyptic number.
It is an amenable number.
198312004889 is a deficient number, since it is larger than the sum of its proper divisors (1).
198312004889 is an equidigital number, since it uses as much as digits as its factorization.
198312004889 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 995328, while the sum is 53.
The spelling of 198312004889 in words is "one hundred ninety-eight billion, three hundred twelve million, four thousand, eight hundred eighty-nine".
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