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1983986957 is a prime number
BaseRepresentation
bin111011001000001…
…0011110100001101
312010021012222110102
41312100103310031
513030400040312
6524511420445
7100110416351
oct16620236415
95107188412
101983986957
119289aa847
12474524725
1325805b8a4
1414b6cb461
15b929cec2
hex76413d0d

1983986957 has 2 divisors, whose sum is σ = 1983986958. Its totient is φ = 1983986956.

The previous prime is 1983986909. The next prime is 1983986971. The reversal of 1983986957 is 7596893891.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 1567051396 + 416935561 = 39586^2 + 20419^2 .

It is an emirp because it is prime and its reverse (7596893891) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 1983986957 - 222 = 1979792653 is a prime.

It is a super-2 number, since 2×19839869572 = 7872408491092239698, which contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 1983986893 and 1983986902.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1983986987) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 991993478 + 991993479.

It is an arithmetic number, because the mean of its divisors is an integer number (991993479).

Almost surely, 21983986957 is an apocalyptic number.

It is an amenable number.

1983986957 is a deficient number, since it is larger than the sum of its proper divisors (1).

1983986957 is an equidigital number, since it uses as much as digits as its factorization.

1983986957 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 29393280, while the sum is 65.

The square root of 1983986957 is about 44541.9684904024. The cubic root of 1983986957 is about 1256.5495073868.

The spelling of 1983986957 in words is "one billion, nine hundred eighty-three million, nine hundred eighty-six thousand, nine hundred fifty-seven".