19846704241253 has 2 divisors, whose sum is σ = 19846704241254. Its totient is φ = 19846704241252.

The previous prime is 19846704241181. The next prime is 19846704241297. The reversal of 19846704241253 is 35214240764891.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 14729146352449 + 5117557888804 = 3837857^2 + 2262202^2 .

It is a cyclic number.

It is not a de Polignac number, because 19846704241253 - 2¹⁴ = 19846704224869 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (19846704244253) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 9923352120626 + 9923352120627.

It is an arithmetic number, because the mean of its divisors is an integer number (9923352120627).

It is a 1-persistent number, because it is pandigital, but 2⋅19846704241253 = 39693408482506 is not.

Almost surely, 2^{19846704241253} is an apocalyptic number.

It is an amenable number.

19846704241253 is a deficient number, since it is larger than the sum of its proper divisors (1).

19846704241253 is an equidigital number, since it uses as much as digits as its factorization.

19846704241253 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 11612160, while the sum is 56.

The spelling of 19846704241253 in words is "nineteen trillion, eight hundred forty-six billion, seven hundred four million, two hundred forty-one thousand, two hundred fifty-three".