Base | Representation |
---|---|
bin | 111011001011111… |
… | …1101100111000001 |
3 | 12010101222220102222 |
4 | 1312113331213001 |
5 | 13031403240103 |
6 | 525022420425 |
7 | 100133443334 |
oct | 16627754701 |
9 | 5111886388 |
10 | 1985993153 |
11 | 92a050061 |
12 | 475131715 |
13 | 2585b1aa1 |
14 | 14ba9061b |
15 | b9547638 |
hex | 765fd9c1 |
1985993153 has 2 divisors, whose sum is σ = 1985993154. Its totient is φ = 1985993152.
The previous prime is 1985993129. The next prime is 1985993231. The reversal of 1985993153 is 3513995891.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 1569506689 + 416486464 = 39617^2 + 20408^2 .
It is a cyclic number.
It is not a de Polignac number, because 1985993153 - 26 = 1985993089 is a prime.
It is a Sophie Germain prime.
It is a Curzon number.
It is a junction number, because it is equal to n+sod(n) for n = 1985993095 and 1985993104.
It is not a weakly prime, because it can be changed into another prime (1985993123) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 992996576 + 992996577.
It is an arithmetic number, because the mean of its divisors is an integer number (992996577).
Almost surely, 21985993153 is an apocalyptic number.
It is an amenable number.
1985993153 is a deficient number, since it is larger than the sum of its proper divisors (1).
1985993153 is an equidigital number, since it uses as much as digits as its factorization.
1985993153 is an odious number, because the sum of its binary digits is odd.
The product of its digits is 1312200, while the sum is 53.
The square root of 1985993153 is about 44564.4830891148. The cubic root of 1985993153 is about 1256.9729032098.
The spelling of 1985993153 in words is "one billion, nine hundred eighty-five million, nine hundred ninety-three thousand, one hundred fifty-three".
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